3/(s-4)+1=14/(s^2-16)

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Solution for 3/(s-4)+1=14/(s^2-16) equation:


D( s )

s-4 = 0

s^2-16 = 0

s-4 = 0

s-4 = 0

s-4 = 0 // + 4

s = 4

s^2-16 = 0

s^2-16 = 0

1*s^2 = 16 // : 1

s^2 = 16

s^2 = 16 // ^ 1/2

abs(s) = 4

s = 4 or s = -4

s in (-oo:-4) U (-4:4) U (4:+oo)

3/(s-4)+1 = 14/(s^2-16) // - 14/(s^2-16)

3/(s-4)-(14/(s^2-16))+1 = 0

3/(s-4)-14*(s^2-16)^-1+1 = 0

3/(s-4)-14/(s^2-16)+1 = 0

(3*(s^2-16))/((s-4)*(s^2-16))+(-14*(s-4))/((s-4)*(s^2-16))+(1*(s-4)*(s^2-16))/((s-4)*(s^2-16)) = 0

3*(s^2-16)-14*(s-4)+1*(s-4)*(s^2-16) = 0

s^3+3*s^2-4*s^2-14*s-16*s+8+64 = 0

s^3-s^2-30*s+72 = 0

s^3-s^2-30*s+72 = 0

s^3-s^2-30*s+72 = 0

{ 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 8, -8, 9, -9, 12, -12, 18, -18, 24, -24, 36, -36, 72, -72 }

1

s = 1

s^3-s^2-30*s+72 = 42

1

-1

s = -1

s^3-s^2-30*s+72 = 100

-1

2

s = 2

s^3-s^2-30*s+72 = 16

2

-2

s = -2

s^3-s^2-30*s+72 = 120

-2

3

s = 3

s^3-s^2-30*s+72 = 0

3

s-3

s^2+2*s-24

s^3-s^2-30*s+72

s-3

3*s^2-s^3

2*s^2-30*s+72

6*s-2*s^2

72-24*s

24*s-72

0

s^2+2*s-24 = 0

DELTA = 2^2-(-24*1*4)

DELTA = 100

DELTA > 0

s = (100^(1/2)-2)/(1*2) or s = (-100^(1/2)-2)/(1*2)

s = 4 or s = -6

s in { -6, 4, 3}

(s+6)*(s-4)*(s-3) = 0

((s+6)*(s-4)*(s-3))/((s-4)*(s^2-16)) = 0

((s+6)*(s-4)*(s-3))/((s-4)*(s^2-16)) = 0 // * (s-4)*(s^2-16)

(s+6)*(s-4)*(s-3) = 0

( s+6 )

s+6 = 0 // - 6

s = -6

( s-3 )

s-3 = 0 // + 3

s = 3

( s-4 )

s-4 = 0 // + 4

s = 4

s in { 4}

s in { -6, 3 }

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